.02(20(3x^2+1))=0

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Solution for .02(20(3x^2+1))=0 equation:


Simplifying
0.02(20(3x2 + 1)) = 0

Reorder the terms:
0.02(20(1 + 3x2)) = 0
0.02((1 * 20 + 3x2 * 20)) = 0
0.02((20 + 60x2)) = 0
(20 * 0.02 + 60x2 * 0.02) = 0
(0.4 + 1.2x2) = 0

Solving
0.4 + 1.2x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-0.4' to each side of the equation.
0.4 + -0.4 + 1.2x2 = 0 + -0.4

Combine like terms: 0.4 + -0.4 = 0.0
0.0 + 1.2x2 = 0 + -0.4
1.2x2 = 0 + -0.4

Combine like terms: 0 + -0.4 = -0.4
1.2x2 = -0.4

Divide each side by '1.2'.
x2 = -0.3333333333

Simplifying
x2 = -0.3333333333

Reorder the terms:
0.3333333333 + x2 = -0.3333333333 + 0.3333333333

Combine like terms: -0.3333333333 + 0.3333333333 = 0.0000000000
0.3333333333 + x2 = 0.0000000000

The solution to this equation could not be determined.

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